Not really. You can't quantify the difference in pain of pain A and pain B; all you can say is that one is worse than the other.
Why do you think that?
We could classify the set of all pains as a partially ordered set. That is, we have an operation <= with the following properties:
A<=A for all A in our set of pains.
If A<=B and B<=A then A=B for all A and B in our set of pains.
If A<=B and B<=C then A<=C for all A, B, and C in our set of pains.
For us to be able to take operations such as A-B, we would need a metric. As you said, such a metric would depend on the individual interpretation (such as it is, a subjective measure), and so such a set would not have a single metric but a set of all possible metrics such that the partial ordering is respected (that is, while everyone may agree that pain A is worse than pain B, the degree of which may scale from infinitesimal to infinite).
Ah, but you see, the same argument applies to
your mathematics! Not everybody agrees on whether Pain A is worse than Pain B, so the partial ordering is subjective, just like my metric.
What you are claiming is specifically that for all possible metrics d for every epsilon>0 there exists an integer N such that n>N=>d(torture, dustn)<epsilon.
I'm not quite getting you here. What does d(something) mean?
This is the definition of a limit of a sequence under an ambiguous metric, with a sequence {dustn} which you claim converges to torture for all possible metrics.
I don't think that's what I claimed. I think that dust
n converges to
infinity.
Now, I did not assume that dust simply increases by scaling, since our metric is undefined here- d(dust, 2*dust) can equal anything, we do not know. You claim it is 1, but that requires an explicit metric, which you said yourself is a subjective evaluation.
But... but you're saying that the second person to receive a dust speck matters
less than the first! Why would you
think that?!
So, what do we know about our lovely infinite dust sequence? Well, we know it is monotonic increasing, or else at some point more people suffering makes the suffering better, which makes no sense. We would like for it to converge- hence, it is bounded.
"I want it to be bounded, therefore it is bounded." What? Anyway, I don't think it converges. I think that an arbitrarily large group receiving dust specks feels an arbitrarily large amount of suffering.
Now it is a question of what it converges to. We know that the definition of convergence is as follows:
For every epsilon>0 there exists an N such that n>N=>d(an,a)<epsilon
We would like to claim that dust converges to torture under all metrics. We know that d(x,z)<=d(x,y)+d(y,z), since it is part of the definition of a metric. Hence, d(dustn,torture)<=d(dustn,dustm)+d(dustm,torture), for all m>n. Or, to rearrange, d(dustn,torture)-d(dustm,torture)<=d(dustn,dustm), for all m>n. So let's look at the sequence of d(dustn,dustm), with n fixed and m increasing.
We know that the sequence is monotonically increasing. We do not know if it is strictly increasing, and we do not know that it is bounded. If, under a metric, it is not strictly increasing (that is, there exists an m1 and an m2 such that d(dustn,dustm1)=d(dustn,dustm2), then we would consider all pains by dust equal to torture. If we consider that we do not know the number of dust-sufferers at any given point in time, and there is ambiguity in our n's and m's, then it is inherently monotonic across all evaluations (since n versus n+1 would be effectively the same because they are indistinguishable, but n versus n+100 would be distinguishable), and we would get this result.
The main issue arises if it is bounded- that is, there is a limit to what we can consider to be "suffering" by dust. There exists an M such that |dustn|<=M for all n. This is not to say that we necessarily "stop caring" about additional pain- there is no explicit requirement that we have equality, only that we have less than or equality, so it is entirely possible that |dustn|<M for all n. If M<torture, then d(dustn,M)<=|torture|, which violates are triangle inequality. There are an infinite number of metrics where this can be true, even if in the one you originally worked with, your metric was Euclidean distance. Ergo, there are an infinite number of metrics where there does not exist a finite number of dust-sufferers such that torture would be a viable alternative.
And this is why armchair mathematics as a philosophical system is absolutely ridiculous. Especially when the people making the arguments don't actually have a proper understanding of the mathematics involved.
I can't really respond to this until I know what d(something, something else) means, but it feels like you're just pulling numbers and concepts out of thin air. Why the hell should infinite pain be bounded?!