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[nogoodnames]

It looks like you managed to combine two lines of code. Judging by the comment, this line:

Code: [Select]

JOptionPane.showMessageDialog(null, bankAccounts.newBankAccount(i).getAccountId() + getPassword());//DISPLAY MESSEGE OF CREATION
...should be outside the for loop and should read like this:

Code: [Select]

JOptionPane.showMessageDialog(null, newBankAccount().getAccountId() + newBankAccount.getPassword());//DISPLAY MESSEGE OF CREATION
That should access the details of the newly created account.

Inside the for loop, if you want to have it display the details of every account in the array, it should look like this:

Code: [Select]

JOptionPane.showMessageDialog(null, bankAccounts[i].getAccountId() + bankAccounts[i].getPassword());
That will access the account at index i and display the information.

Disclaimer: I have never really used Java, but I assume it's using the same syntax as every other C-based language.

[DragonDePlatino]

Having a hard time wrapping my head around this one. In C++, what is the most concise statement that passes if *only one* of my conditions is true?

Code: [Select]

bool x = false;
bool y = true;
bool z = true;

if(only x, only y or only z)
{
do stuff;
}

If I try (x || y || z), my statement continues at y and ignores z. I think I could do this with a monstrous nested if statement (I have way more bools) but I'd like to know if there's a better way before I attempt that.

EDIT:

Silly me! I should just try if(x + y + z == 1). Never mind.

[Mephisto]

Having a hard time wrapping my head around this one. In C++, what is the most concise statement that passes if *only one* of my conditions is true?

Code: [Select]

bool x = false;
bool y = true;
bool z = true;

if(only x, only y or only z)
{
do stuff;
}

If I try (x || y || z), my statement continues at y and ignores z. I think I could do this with a monstrous nested if statement (I have way more bools) but I'd like to know if there's a better way before I attempt that.

EDIT:

Silly me! I should just try if(x + y + z == 1). Never mind.

Sounds like an XOR. x^y^z

[scrdest]

I'm building an actions tree for an action planner AI in a C++-esque language. It gets a goal on start, loops through actions that have an effect matching the goal, and checks requirements for these actions.

If they are not met already it goes through the same process for a subbranch with meeting the requirement as a goal, if it is the path is considered a valid path, and once all paths are found, it uses A* to find an optimal plan of actions.

Now, I've got the tree-building pretty much done, but I need advice how to access the branches when the paths are all set up.

Right now, I have a variable incremented on each iteration of the loop that doubles as a pointer to the list position of the action, in other words if we have three total possible actions A, B, C they are being pointed to as 1, 2, 3; if you need to do B to be able to do A, it looks at all the possible actions, once again the same ABC, and among them finds a valid path in the action B, making it 1.2, if B needs C to be done to work - 1.2.3 and so on.

I'm not sure how to put that together that way, though, and I wonder if there's a better way to access these.

[Bauglir]

Sounds like an XOR. x^y^z

This will run any time an odd number of conditions are true, so it doesn't quite work.

[TheBiggerFish]

((x^y)^z)^a...?

[DragonDePlatino]

Thanks for the help, but I'll be sticking to if(x + y + z == 1).

For context, I'm checking if only one of 8 directional keys has been hit before I handle input in my game. (x NAND y) AND (x NAND z) AND (y NAND z) works, but becomes incredibly complicated when testing 8 booleans against each other. x^y^z worked, but had that odd-numbered problem.

[MagmaMcFry]

Sounds like there is a better way to do this though. What are these 8 keys controlling?

[TheBiggerFish]

Would ((x XOR y) XOR z) XOR a...
Work though?
Purely curiosity at this point...

[3man75]

Spoiler (click to show/hide)

Code: [Select]

private int accountId;

private double accountBalance;

private static double annualInterestRate = 0.045;

private static java.util.Date dateCreated = new java.util.Date();

private String name;

private String password = "";

public BankAccount() {//ADDED TWO PARAMETERS
//NO ARGUMENT CONSTRUCTOR
accountId = (int) (Math.random() * 9000) + 999;
//RANDBETWEEN
setAccountBalance(0);
Random passcode = new Random();
char charcs = (char)(passcode.nextInt(26) + 'a');
//Added string.
}

Can someone help me make this password work? I"m trying to make a 4 letter password fit into my constructors. I thought I had it working but no.

[DragonDePlatino]

Sounds like there is a better way to do this though. What are these 8 keys controlling?

For my first game (and first C++ program, really) I'm making a roguelike. Like most roguelikes, each directional key corresponds to an x and y direction, like so:

Spoiler (click to show/hide)

Code: [Select]

enum {x, y, sdl_scancode};
enum {DOWNLEFTKEY, DOWNKEY, DOWNRIGHTKEY, LEFTKEY, RIGHTKEY, UPLEFTKEY, UPKEY, UPRIGHTKEY, QUITKEY};
const std::vector< std::vector<int> > KEYLIST =
   {{-1, 1, SDL_SCANCODE_KP_1},     // DOWNLEFTKEY
{0, 1, SDL_SCANCODE_KP_2},      // DOWNKEY
{1, 1, SDL_SCANCODE_KP_3},      // DOWNRIGHTKEY
{-1, 0, SDL_SCANCODE_KP_4},     // LEFTKEY
{1, 0, SDL_SCANCODE_KP_6},      // RIGHTKEY
{-1, -1, SDL_SCANCODE_KP_7},    // UPLEFTKEY
{0, -1, SDL_SCANCODE_KP_8},     // UPKEY
{1, -1, SDL_SCANCODE_KP_9},    // UPRIGHTKEY
{SDL_SCANCODE_ESCAPE}};         // QUITKEY

                           
I then take in inputs and match each key to a direction:

Spoiler (click to show/hide)

Code: [Select]

if( getinput && (KEYHIT[KEYLIST[UPKEY][sdl_scancode]] + KEYHIT[KEYLIST[DOWNKEY][sdl_scancode]] +
KEYHIT[KEYLIST[LEFTKEY][sdl_scancode]] + KEYHIT[KEYLIST[RIGHTKEY][sdl_scancode]] +
KEYHIT[KEYLIST[UPLEFTKEY][sdl_scancode]] + KEYHIT[KEYLIST[UPRIGHTKEY][sdl_scancode]] +
KEYHIT[KEYLIST[DOWNLEFTKEY][sdl_scancode]] + KEYHIT[KEYLIST[DOWNRIGHTKEY][sdl_scancode]]) == 1) // Check if accepting input and only one directional key was hit
{
for(int key = 0; key < 8; key++) // Iterate through all keys in KEYLIST
{
if(KEYHIT[KEYLIST[key][sdl_scancode]]) // If a key is hit, add that corresponding key's velocity
{
if(grounded) // Only change x and y velocity if grounded
{
vel[x] = KEYLIST[key][x];
vel[y] = KEYLIST[key][y];
}
}
}
}

   
Originally, I had a big string of if-else statements for each button but this is much shorter. I think I've sacrificed some of my readability, though.

[Putnam]

Switch statement?

[Orange Wizard]

I used a python dictionary of {keycode:command} that actually worked pretty well but I ditched it because a huge string of if::else statements requires less thinking, and I'm not very good at thinking.

[MagmaMcFry]

<roguelike>

If your roguelike is turn-based, I suggest using the keypress events instead of checking for down-ness. If your roguelike is realtime, then why not just find the first pressed key and use that?

[EnigmaticHat]

<roguelike>

If your roguelike is turn-based, I suggest using the keypress events instead of checking for down-ness. If your roguelike is realtime, then why not just find the first pressed key and use that?

Its safer in games to check for a switch from down > up status, unless your game specifically requires the ability to hold down buttons.  Negates the impact of accidental button presses and allows people to reconsider their actions, which is especially important in roguelikes.  Also prevents those glitches where the game thinks a button is being held down when its not.