Question for the more physics-minded folks out there:
Breaking c seems relatively simple in a relative frame. You send one observer at 0.55c in one direction. You send another observer at 0.55c in the opposite direction. To each observer's relative frame, the other is moving at 1.1c, correct?
For one, I always wondered what the hell that would look like. Would they be seeing an after-image? Would it be like a Doppler shift from hell?
Wouldn't the one observer X appear to the other Y as not having left the starting point until just after Y stopped?
...Wait, did you mean sending them away from each other or against each other? Because I was thinking away.
Should apply either way. If towards each other, the opposite observer should (if I'm understanding everything right) be red-shifted like hell but would still be perceptible, because light reflected off of them would still be outracing them. But then, the incoming light itself is travling at 1.55
c relative to the observer, isn't it?
If away, then it gets conceptually tricker (for me, at least). The relative velocity would be -1.1
c, which would seem to mean that their actual position would be continually outstripping their perceivable position. In short, you'd be seeing a blue-shifted afterimage of where they *were* some time prior. Which is sort of how it works for stellar objects anyways (when we see a distant star, we're seeing the star as it actually was hundreds or thousands of years ago), but only more so.
This is one of those things that I've never understood. It would seem that because virtually nothing in the universe is at total rest, any light traveling in an opposite vector to that of an observer is always ever so slightly greater than 1
c, isn't it?
For one, I always wondered what the hell that would look like. Would they be seeing an after-image? Would it be like a Doppler shift from hell?
Second, I haven't read the paper, but did they account in any way for the Earth's orbital/rotational motion and Sol's movement? Maybe neutrinos operate somehow so as to be outside the relative observer frame? If that even makes sense....
They may not have needed to Redking. Any apparatus for testing velocity that could be used would necessarily be just as effected by they earth's rotation and the pull from Sol's movement.
What COULD have happened though is that these neutrinos are partially or totally unaffected by the earth/ Sol's movement. That's would be just as crazy though.
Yeah, that's what I was trying to get at. That maybe neutrinos are somehow "pegged" to the fabric of spacetime and so are still constrained by
c, just not in a relative frame (as light itself apparently isn't). That still doesn't explain why light in the relative frame of Earthbound observers still appears to travel slower than these neutrino bursts did, though....unless
c isn't a universal constant. And there have been experiments that show
c can be heavily modified by environmental conditions (that's probably not the right term, but...) like the guys who slowed light down to 38mph in a vat of hypercooled sodium. Since neutrinos don't seem to interact with matter in the same way that most particles do, it makes a certain amount of sense that this may be because they're.....I dunno, "meta-particles" for lack of a better term?
I'm sorry, I know I'm being a complete physics n00b here but I'm just trying to wrap my brain around it.
EDIT: Okay, thanks for the explanation. I'll have to brush up on Lorentz. All I know of the name is in application to fractals.