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[MaximumZero]

I don't really understand references all that well, but I have a feeling that when I do, I will understand why The Toad made ampersands into demons.

[Levi]

Anybody happen to know if python has something like the  ? : operator?  I keep wanting to have conditionals in my expressions but I'm not seeing a way to do it.

[Mephisto]

Anybody happen to know if python has something like the  ? : operator?  I keep wanting to have conditionals in my expressions but I'm not seeing a way to do it.

Kind of. Check out the FAQ which, while for Python 2.x, is also valid for 3.x,

or Pep 308, which discusses why Python is different in this regard.

[Levi]

Anybody happen to know if python has something like the  ? : operator?  I keep wanting to have conditionals in my expressions but I'm not seeing a way to do it.

Kind of. Check out the FAQ which, while for Python 2.x, is also valid for 3.x,

or Pep 308, which discusses why Python is different in this regard.

Perfect, that is good enough for me.  Thanks!

[Max White]

Ok guys, the language is Java, and the problem is Keyboard input. I imagine this is common enough for somebody to have covered it, but some quick research turns over nothing.
I want something that will wait for keyboard input, then return a single character without use of a console. Something along these lines...

Code: [Select]

Keyboard keyboard = new Keyboard();
char input = keyboard.getChar();

Or using a static class would also be good, I see no reason why not. Either way, anything out there?

[Jopax]

Righto, homework help time.
Working in C++ right now and one of the problems we have to solve is a program that takes three real numbers from the user input and then sorts them by size, we can only use the IF command to do so (no loops or anything).Now I don't need the whole solution, just how should I approach this since I have no idea in which way I could utilize the IF commands in order to compare all the numbers and then write them out without making it incredibly huge and convulted.

[Darvi]

Similar problem here. Gotta find the biggest number out of three using C.

I have never worked with C before. It's close enough to C++ that I can actually write something, but different enough for not to work at all.

Oh, and we don't have a compiler yet so we gotta do it on notepad.

Fun.

[Virex]

Righto, homework help time.
Working in C++ right now and one of the problems we have to solve is a program that takes three real numbers from the user input and then sorts them by size, we can only use the IF command to do so (no loops or anything).Now I don't need the whole solution, just how should I approach this since I have no idea in which way I could utilize the IF commands in order to compare all the numbers and then write them out without making it incredibly huge and convulted.

You just first compare 2 numbers, store them in the right order, then compare the third value first to the highest of the two and then if needed to the lowest. That should tell you where to put it relative to the two already stored values.

Spoiler: Pseudocode, in case you're realy stuck (click to show/hide)

StupidIfSortProblem(val1, val2, val3)
valSet = int[3]
if val1 >= val2
    valSet = [val1, val2, null]
if val3 >= valSet(1)
    valSet = [val3, valSet(1), valSet(2)]
else if val3 <= valSet(2)
    valSet = [valSet(1), valSet(2), val3]
else
    valSet = [valSet(1), val3, valSet(2)]
end

Note: Writing it out like this for values larger than 4 is going to hurt your head (not to mention your hands), but the pattern is regular, so you could just write a compiler macro to handle it for you. also the comparison of val 3 would probably more elegantly handled with a case statement.

[Mephisto]

Ok guys, the language is Java, and the problem is Keyboard input. I imagine this is common enough for somebody to have covered it, but some quick research turns over nothing.
I want something that will wait for keyboard input, then return a single character without use of a console. Something along these lines...

Code: [Select]

Keyboard keyboard = new Keyboard();
char input = keyboard.getChar();

Or using a static class would also be good, I see no reason why not. Either way, anything out there?

I was a little unsure myself, so with a bit of Googling: Reading input character by character

[Nadaka]

Ok guys, the language is Java, and the problem is Keyboard input. I imagine this is common enough for somebody to have covered it, but some quick research turns over nothing.
I want something that will wait for keyboard input, then return a single character without use of a console. Something along these lines...

Code: [Select]

Keyboard keyboard = new Keyboard();
char input = keyboard.getChar();

Or using a static class would also be good, I see no reason why not. Either way, anything out there?

Off the top of my head, you can create a gui text box, set its focus and either loop through with a read and purge of its value or wait for a keydown event.

[Jopax]

Solved it, took quite a while since i kept coming up with new possibilities that had to be accounted for X)

Thanks a bunch for the help

[MaximumZero]

Speaking of homework, I seem to be stuck.

Language: Visual Basic
Mission (should you choose to accept it): Take a variable on one form, put it in a second form, and keep it around after the first form closes.

[Virex]

I don't know visual basic at all, but can't you just copy the variable by value and stow it away somewhere safe?

[Nadaka]

The form definition is just a class. The Form in the application is just an object. Add a public member to the form definition of form 2 and set it from form 1.

[Darvi]

There seems to be a problem in my code when it comes to assigning values to an array of integers. Instead of the intended rand()%100 I get crazy values like -1216353508 -1078954956 -1078954948 -163754450

Code: [Select]

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <time.h>

void sort (int a[]){
   int unsorted = 0;
   do{
      unsorted = 0;   
      for (int i = 0; i < 20; i++){   
         if (*(a+i)>*(a+i+1)){
            int t = *(a+i+1);
            *(a+i+1) = *(a+i);
            *(a+i) = t;
            unsorted = 1;
            }   
         }         
      }while(unsorted);
}

int main(){
===========================
   int l1 = 5, l2 = 5, l3 = l1 + l2, t1[l1], t2[l2], t3[l3];
   srand(time(NULL));
   for (int i = 0; i < l2; i++){*(t2+i) = rand()%100;};
   for (int i = 0; i < l1; i++){*(t1+i) = rand()%100;};
   sort(t1);
   sort(t2);
===========================
   int i = 0, j = 0;
   while ((i < l1)&&(j < l2)){
      if (*(t1+i) < *(t2+j)){
         *(t3+i+j) = *(t1+i);
         i++;
      }else{
         *(t3+i+j) = *(t2+j);
         j++;
      }
   }
   while (i < l1){
      *(t3+i+j) = *(t1+i);
      i++;
   }
   while (j < l2){
      *(t3+i+j) = *(t2+j);
      j++;
   }
   for (int k = 0; k < l3; k++){printf("%d ",*(t3+k));}
   printf("\n");
   return 0;
}
The troublemaker's the t2 array but I'm too lazy incapable of noticing any mistake.
The bit between the equal signs is the part where I assume the problem is because I tried the code with the rest commented out but the problem still remaining.

E: Welp it appears that the sorting function seems to be the cause of the mistake. Gotta fix that.