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[Baffler]

Whoops, that should be 0°C. Of all the typos...

[TheBiggerFish]

But yeah, add them up, subtract the phase change, then divide it back out.  Or something?  I don't actually know.

[Culise]

To go from mL to grams, you'll also want the density of water, but that's so trivial that it's barely worth noting.  My assumption is that they want you to go with the bog-standard 1 g/cm³ (at 4°C) rather than tracking its variability over different temperatures, which means that 150mL of water masses a convenient 150g, since it's a only a  difference of something like 1.8E-3 grams for the difference between 4°C and 20°C.  That's just me being pedantic, though, since you specifically mentioned the possibility of needing more physical constraints, and since you already corrected the error that put your poor 20°C ice cube under over a GPa of pressure.

Any rate, if I recall properly (and it's been even longer for me than TheBigger Fish), what you want to do is basically use conservation of energy - the energy that goes into melting and heating your ice to your equilibrium temperature T is the same as the energy that cools the rest of the system from 20°C to the same equilibrium temperature T.  Regarding the ice, the first bit requires your heat of fusion; the second bit is a more conventional temperature change using the specific heat (of water, since it's no longer solid).  Since the ice conveniently starts at its melting point of 0°C, you don't actually seem to need the specific heat of ice as far as I can tell; there is no thermal change that takes place while the ice is actually still solid, since it immediately melts.  For Q as the heat in the system and q as the specific heats...

Q_melt + Q_{warming water} + Q_{cooling water} + Q_{cooling cup} = 0
Q_melt + Q_{warming water} = - ( Q_{cooling water} + Q_{cooling cup} )
(q_fusion * m_ice) + (q_water * m_ice * ΔT_ice) = - ( (q_water * m_water * ΔT_{cup and water}) + (q_cup * m_cup * ΔT_{cup and water}) )
        For ΔT_{cup and water} = T - 20 and ΔT_ice = T - 0 = T

Shove stuff around and solve for T - that's your equilibrium temperature where everything ends up at.  At least, assuming I remember this right.  I am a bit out of practice.

((Also, can I just take this opportunity to reiterate that customary units are horrifying? I dusted off my old thermal textbook for a quick refresher and was confronted by visions of Btu/hr.))

[GrizzlyAdamz]

I'm stumped by the 'Min' & '0.99,'
What do they mean?

Spoiler (click to show/hide)

[Graknorke]

I'm stumped by the 'Min' & '0.99,'
What do they mean?

Spoiler (click to show/hide)

What's the context?

[GrizzlyAdamz]

http://fallout.wikia.com/wiki/Damage_Resistance#Damage_Reduction_formula

[Culise]

Looks like pseudo-code.  MIN(X,Y,...) denotes the lowest value in the data set X,Y,... would be returned.  So, in this case, the game calculates the formula, compares it to the number 0.99, and returns the lower of the two. 

[i2amroy]

Looks like pseudo-code.  MIN(X,Y,...) denotes the lowest value in the data set X,Y,... would be returned.  So, in this case, the game calculates the formula, compares it to the number 0.99, and returns the lower of the two.

This right here.

[Amperzand]

This seems relevant to my current issues.

[TheBiggerFish]

Which are?

[Amperzand]

Not currently anything in particular, but the term's only half done, and by prior evidence help will be needed. Most of what I have to do right now is just for practice.

[TheBiggerFish]

Ah.

[Amperzand]

Effectively PTWing, but with a thing to say.

[Skyrunner]

I just started my Probability & Statistics class, and there is a loot of proofs going on

[Amperzand]

Oh jeez.