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Author Topic: Systematically Choose Who Wins: Game Over  (Read 25753 times)

Diablous

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Re: Systematically Choose Who Wins: Day 3
« Reply #150 on: August 06, 2010, 11:00:27 am »

I guess I'll vote for Toaster. For the cabal!
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Quote from: Solifuge
A catgirl, whom oft it would please
To dine on a pizza, with cheese,
Thought it was quite fine
To be partly feline,
Excepting the hairballs and fleas.

Toaster

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Re: Systematically Choose Who Wins: Day 3
« Reply #151 on: August 06, 2010, 11:23:01 am »

I can't vote for myself, but Diablous is a cool dude.
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HMR stands for Hazardous Materials Requisition, not Horrible Massive Ruination, though I can understand how one could get confused.
God help us if we have to agree on pizza toppings at some point. There will be no survivors.

Lucus Casius

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Re: Systematically Choose Who Wins: Day 3
« Reply #152 on: August 06, 2010, 12:14:56 pm »

Pandar, because god damn it I want Man of SCIENCE!!! updated.
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Criptfeind

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Re: Systematically Choose Who Wins: Day 3
« Reply #153 on: August 06, 2010, 01:03:39 pm »

Lucus Casius, Solifuge, Toaster

1d3=2

Solifuge has been chosen today.

All hail the cabal!

We still have slots open, who wants to win?
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Diablous

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Re: Systematically Choose Who Wins: Day 3
« Reply #154 on: August 06, 2010, 01:06:29 pm »

Okay. Unvote. Sorry Toaster. Solifuge, your victory is at hand!
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Quote from: Solifuge
A catgirl, whom oft it would please
To dine on a pizza, with cheese,
Thought it was quite fine
To be partly feline,
Excepting the hairballs and fleas.

Cheddarius

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Re: Systematically Choose Who Wins: Day 3
« Reply #155 on: August 06, 2010, 03:10:38 pm »

Non-Partisan Analysis By A Dude With A Basic Understanding of Mathematics/Probability And Too Much Time On His Hands

Criptfiend's plan is flawed. For one thing, he has to keep recruiting cabal members in order to get a sure majority.

FIRST TURN
There are 14 players in the game, eight in the cabal.
Six will win.
Eight players vote for Criptfiend, assuring his victory.

SECOND TURN
There are 13 players in the game, seven in the cabal.
Five more will win.
Seven players vote for some cabal member, assuring his victory (the random roll, by the way, is not secure. Criptfiend can easily, easily fake them. Here's how: suppose Bill is his friend, and Bill is #3. He rolls a 1d7 repeatedly until he gets a 3. Then he posts that roll. Easy as pie. One reliable way is to say "Tomorrow, I will take the opening price of the NYSE, take the last two digits (the cents, which are essentially random given how much it wavers), and take that modulus the number of players, and that will be the person we vote for. It is completely transparent, anyone can verify it, and it cannot be changed.

THIRD TURN
There are twelve players in the game, six in the cabal. Oh no! He doesn't have enough for victory! He has to recruit one more player; there are seven in the cabal now.
Four more will win. (Note that the "crude" chance of winning has declined to 4/7 or 57%. I will calculate the "true" chance of winning later)
Seven players vote for the cabal member, assuring victory.

FOURTH TURN
There are 11 players in the game, 6 cabal.
3 more will win.
6 vote for the chosen cabal member, assuring victory.

FIFTH TURN
There are 10 players in the game, 5 cabal. One cabal member is recruited, now 6 cabal.
2 more will win. (Crude chance of cabal winning has declined to 33%)
6 vote for the chosen, assuring victory.

SIXTH TURN
There are 9 players in the game, 5 cabal.
1 more will win. (20% win chance)
Five people vote for the chosen, who wins.

Now that is the point that Pandarsenic illustrated - even if it works at the start, it will surely collapse later, when there are fewer cabal members. To keep a majority you will have to get more and more members, few of whom will win. Now we'll calculate the "true" win chance.

Criptfiend touts his cabal idea on the first turn. You figure, hey, why not? I want to win, right? That turn, you have a 0 chance of winning, since Cript will win.
The second turn, you have a 1/7 chance of winning.
The third turn, you have a 1/7 chance of winning, since a new member had to be recruited.
The fourth turn, you have a 1/6 chance of winning.
The fifth turn, you have a 1/6 chance of winning.
The sixth turn, you have a 1/5 chance of winning.
The total chance of winning is: (chance that you'll win the first round) + (chance that you'll lose the first round but win the second) + (chance that you'll win the first two rounds but win the third)... etc.

It's not them all added up, because obviously you can't win if you've already won, so you have to lose the first to win the second. Otherwise you get dumb stuff like "I have a 1/2 chance of getting heads, so if I flip twice in a row my chance of getting heads is 50%+50%=100%!" No, two tails is unlikely but possible.

So. The total chance is 0+(1/7)+(6/7)(1/7)+(6/7)(6/7)(1/6)+(6/7)(6/7)(5/6)(1/6)+(6/7)(6/7)(5/6)(5/6)(1/5) = 59.2%. Just over half; far from the glorious 85% he promised (which, as Pandar said, doesn't make any sense anyways. 85% = 17/20. So does that mean there are 20 cabal members and 17 winners? Huh?)

And the chance of winning if you join later on is even more abysmal; if you join on the third turn, the chance of winning is (1/7)+(6/7)(1/6)+(6/7)(5/6)(1/6)+(6/7)(5/6)(5/6)(1/5) = 52.4%. A few percentage points over half. That's definitely not the almost sure win he promised.

If you join on the fifth turn, the chance is (1/6)+(5/6)(1/5) = 33%. Ouch. (Actually, due to an oversight on my part, the cabal will have to recruit even more members than I thought, since one can't vote for oneself - for example, on the second turn, there will be 6 non-cabal, and seven cabal, and since you can't vote for yourself, only six cabal can vote for a given person, which could result in a tie; thus you would need to recruit already by the second turn)

"But wait!" you cry. "If we don't join the Cabal, we won't win at all!" That may seem so. But it remains, firstly, that Criptfiend has blatantly lied to you (I'd say that he was merely incorrect, but judging by the false statistics he's put up, with no calculations behind them, I doubt it), and another thing...

On the sixth turn, five people will vote for the chosen cabal member, and he will win... or will they?
Imagine you're a cabal member. On the last turn, you aren't chosen. Well, that's to be expected, you had only a 20% of being chosen that turn. Wait! You still have a small chance of winning if you defect and try to gain favor! So you do so. The cabal fails, and the chosen is no better than any other man.

Now, why have you joined the cabal in the first place? The cabal's lure is thus: "Vote for who we want you to, and we'll vote for you later on." Does this hold true?

On the fifth turn, you might follow the rules like always. But this would be unwise. Even if you vote for the chosen person, this will confer you no special advantage on the sixth turn; all will descend into chaos by then and you will have no supporters. Thus, on the fifth turn, if you are not chosen, you should defect and try to get people to vote for yourself.

On the fourth turn, the same thing. On the third turn, and so on.

I would like to point to a game called Prisoner's Dilemma. In one game, the best strategy is to defect, as this is profitable. In a series of games of unknown length, a very good strategy is to play "Tit-For-Tat"; when the other player defects, defect, and when the other player cooperates, cooperate (this strategy attempts to enforce cooperation and thus better both players). But in a series of games where the length is known, well, you're both going to defect on the last round, because you've got nothing to lose. And knowing this, you're going to defect on the penultimate round, because the other guy's not going to cooperate even if you do cooperate... and so on. This is the situation we have here.

The cabal is not stable. Criptfeind lied, deceived you, played you for fools. Every man for himself.
War!
Chaos!
BLOOD FOR THE BLOOD GOD!
« Last Edit: August 06, 2010, 03:12:51 pm by Cheddarius »
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Criptfeind

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Re: Systematically Choose Who Wins: Day 3
« Reply #156 on: August 06, 2010, 03:50:20 pm »

Okay. I skimmed though that and you seem to forgot that
players who have won can still vote.

Really you people that are trying to tear me down are "forgetting" the simplest things.

Your post looks impressive and shit but it is based on lies.
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Criptfeind

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Re: Systematically Choose Who Wins: Day 3
« Reply #157 on: August 06, 2010, 03:59:48 pm »

Non-Partisan Analysis By A Dude With A Basic Understanding of Mathematics/Probability And Too Much Time On His Hands

FIRST TURN
There are 14 players in the game, eight in the cabal.
Eight players vote for Criptfiend, assuring his victory.

SECOND TURNthe random roll, by the way, is not secure. Criptfiend can easily, easily fake them. Here's how: suppose Bill is his friend, and Bill is #3. He rolls a 1d7 repeatedly until he gets a 3. Then he posts that roll. Easy as pie. One reliable way is to say "Tomorrow, I will take the opening price of the NYSE, take the last two digits (the cents, which are essentially random given how much it wavers), and take that modulus the number of players, and that will be the person we vote for. It is completely transparent, anyone can verify it, and it cannot be changed.

THIRD TURN

FIFTH TURN

SIXTH TURN

Criptfiend touts his cabal idea on the first turn. You figure, hey, why not? I want to win, right? That turn, you have a 0 chance of winning, since Cript will win.
The second turn, you have a 1/7 chance of winning.
The total chance of winning is: (chance that you'll win the first round) + (chance that you'll lose the first round but win the second) + (chance that you'll win the first two rounds but win the third)

Okay I deleted all the stuff that were based on faulty assumptions.

Feel free to try again.
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Cheddarius

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Re: Systematically Choose Who Wins: Day 3
« Reply #158 on: August 06, 2010, 04:06:49 pm »

Your post looks impressive and shit but it is based on lies.
The same goes for yours. Provide your calculations, and let's see how well they stand up.
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Criptfeind

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Re: Systematically Choose Who Wins: Day 3
« Reply #159 on: August 06, 2010, 04:11:54 pm »

Sigh.

Why are you people never attacking my math? All you ever say is that I am wrong, you never point out how. I pointed out how you are wrong, now you can try to do the same.

If it helps you that much I will.

This is how it was suppose to work out.

FIRST TURN
There are 14 players in the game, eight in the cabal.
Eight players vote for Criptfiend, assuring his victory.
Six slots left.

SECOND TURN
There are 14 players in the game, eight in the cabal.
Eight players vote for Random cabal member, assuring his victory.
Five slots left.


THIRD TURN
There are 14 players in the game, eight in the cabal.
Eight players vote for Random cabal member, assuring his victory.
Four slots left.


FOURTH TURN
There are 14 players in the game, eight in the cabal.
Eight players vote for Random cabal member, assuring his victory.
Three slots left.


SIXTH TURN
There are 14 players in the game, eight in the cabal.
Eight players vote for Random cabal member, assuring his victory.
Two slots left.


SEVENTH TURN
There are 14 players in the game, eight in the cabal.
Eight players vote for Random cabal member, assuring his victory.
One slot left.


EIGHTH TURN
There are 14 players in the game, eight in the cabal.
Eight players vote for Random cabal member, assuring his victory.
Zero slots left.

One one Cabal member lost.
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Criptfeind

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Re: Systematically Choose Who Wins: Day 3
« Reply #160 on: August 06, 2010, 04:13:05 pm »

Obviously it did not so slide the turns down one and add one to the number of cabal members that have to lose.
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Diablous

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Re: Systematically Choose Who Wins: Day 3
« Reply #161 on: August 06, 2010, 04:14:39 pm »

And the "two cabal members have to lose" thing isn't a problem since Lonewolf and I have volunteered to be those losers.
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Quote from: Solifuge
A catgirl, whom oft it would please
To dine on a pizza, with cheese,
Thought it was quite fine
To be partly feline,
Excepting the hairballs and fleas.

Criptfeind

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Re: Systematically Choose Who Wins: Day 3
« Reply #162 on: August 06, 2010, 04:16:54 pm »

Well yes. There is that.

Also this means we STILL have slots open for those of you who want to win.
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ToonyMan

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Re: Systematically Choose Who Wins: Day 3
« Reply #163 on: August 06, 2010, 04:20:34 pm »

You type long text for no reason lettle bahbees

PANDAR PANDAR PANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDARPANDAR PANDAR
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Cheddarius

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Re: Systematically Choose Who Wins: Day 3
« Reply #164 on: August 06, 2010, 04:22:31 pm »

Why are you people never attacking my math? All you ever say is that I am wrong, you never point out how. I pointed out how you are wrong, now you can try to do the same.
Because you never had any math. All you said were cryptic things about how you had an 80% chance to win, trust me, you know I'm good for it. Where did you get 80%? Where did you get 85.7%? I've seen no math here.

Firstly, you need 9 players to assure a win, because you can't vote for yourself. For someone who says everyone else is forgetting stuff, you seem to be forgetting a bit yourself.

And why exactly do you think the winners will vote "correctly"? They've won, they might as well vote for whoever they feel like voting for, not who you pick randomly.
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