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[Max White]

I notice everyone missed his Tunnel Tube shield. If I recall, tunnel tubes are... hot pink.... 

i thought they were purple :\

When in tree-form, they are indeed pink. As soon as you cut one down and turn it to log-form, it becomes purple.

so, fresh tunnel tube is pink, but once it dries and hardens it becomes darker

Thats gota be the first thing in this game to use any sort of logic other then the dwarven kind.

[Karnewarrior]

I notice everyone missed his Tunnel Tube shield. If I recall, tunnel tubes are... hot pink.... 

i thought they were purple :\

When in tree-form, they are indeed pink. As soon as you cut one down and turn it to log-form, it becomes purple.

so, fresh tunnel tube is pink, but once it dries and hardens it becomes darker

Thats gota be the first thing in this game to use any sort of logic other then the dwarven kind.

BLASPHEMER!

[Vester]

It's a little-known fact that Cave Swallowmen have fantastic abs.

[Julien Brightside]

This was so awesome I began to cry.
Going to refer this thread to the fan art thread.

[Acanthus117]

AWESOME.

[Rose]

and thus, a legend is born.

[Karnewarrior]

50+ pages, here we come!

We should move this to DF Dwarf Mode Discussion, it's more often treaded, and this is more the type of thing you'd find there. This is more for... Fake science on the biology of dwaves and whatnot.

[Dante]

Cave Swallowmen are, in fact, guardians of the Dwarf Fortress world, able to manipulate the fabled RAWs at will. Modifying creature files and descriptions at their whims, they have given themselves both arms and no arms. They are said to be sent from Above, from the Twelfth Bay of the Internets (that is, heaven). It is said that they keep order where there was none, strike down the Bugs of old, Nerf the legendary +elf bone bolt+s spoken of in the ancient tales, and keep company with the angels themselves - Morul, the angel of wisdom and labor, Ironblood, the angel of war and battle, and Cacame, the angel of feasting and vengeance.

Introductory Dwarf Fortress Theology?

The stuff that nightmares are made of.

[zarmazarma]

Hail Armok for this gift of fine Swallow Man, let him be praised.

I suggest that you first fill his chamber with water, then lava, his body will be encased in obsidian. Take said obsidian and turn it into a sword: it is guaranteed to be the most epic one of all time.

[Arkenstone]

You know, I think that the reason he kept on renaming stuff was because killing a forgotten beast with a wooden spear should be enough to make it an artifact 100 times over, and so the game made it an artifact 100 times.

[Cheddarius]

I've read about this somewhere else; some guy's adventurer killed a forgotten beast and started naming his weapon over and over again. So it's a consistent bug.

Arkenstone, let me take a look at the problem of yours...

Spoiler: Working It Out (click to show/hide)

At first it seems impossible. How are we to root a negative and end up with anything reasonable? But looking at the problem as a whole, we have e^result; and as we know, e^ipi = -1; and thus we should be able to have (-1)^(something), which should result in either 1 or -1...
Hmmm. But it is a decimal. So we may in fact end up with -1^0.32535 or something, which wouldn't work out.

Let's try it nonetheless.

Okay, Google gives us the square root as 8.18934689(10^26)i.
And as we know, integral of a constant over [0,1] is obviously just that constant. It's a rectangle, if you visualize it.
So the result is 2*pi*x*f(x)=pi*x*1.63786938E27=... wow! -pi(hugenumber)!
So it's (e^-ipi)^hugenumber = 1^huge number = 1.
All right, ln -1...
Wait, what?
ln 1 would have worked, but ln -1... that doesn't work at all...
Okay, google says it's ipi.
Because.... e^ipi = -1. I see.
So, i*pi. That's the answer, then.

[Coidzure Dreams]

Just found this...  http://memegenerator.net/dfdwarf/ImageMacro/915385/dfdwarf-Hail-Asax-Greatest-Caveswallow-Man-Ever

[Arkenstone]

I've read about this somewhere else; some guy's adventurer killed a forgotten beast and started naming his weapon over and over again. So it's a consistent bug.

Arkenstone, let me take a look at the problem of yours...

Spoiler: Working It Out (click to show/hide)

At first it seems impossible. How are we to root a negative and end up with anything reasonable? But looking at the problem as a whole, we have e^result; and as we know, e^ipi = -1; and thus we should be able to have (-1)^(something), which should result in either 1 or -1...
Hmmm. But it is a decimal. So we may in fact end up with -1^0.32535 or something, which wouldn't work out.

Let's try it nonetheless.

Okay, Google gives us the square root as 8.18934689(10^26)i.
And as we know, integral of a constant over [0,1] is obviously just that constant. It's a rectangle, if you visualize it.
So the result is 2*pi*x*f(x)=pi*x*1.63786938E27=... wow! -pi(hugenumber)!
So it's (e^-ipi)^hugenumber = 1^huge number = 1.
All right, ln -1...
Wait, what?
ln 1 would have worked, but ln -1... that doesn't work at all...
Okay, google says it's ipi.
Because.... e^ipi = -1. I see.
So, i*pi. That's the answer, then.

Spoiler: Wrong :P (click to show/hide)

 You made a few errors there, like saying e^(pi*i*huge number)= (e^(pi*i))^huge number; when it should = (e^pi*i)*(e^huge number).  The e^(pi*i) cancels out the negative, so you should end up with ln(e^the huge number you started with); which means you just end up with whatever you started with.  I made that sig halfway through high school calc class, it's probly due for an update anyways.  The joke, however, should stay the same: trying to solve that formula is as pointless as the game we're talking about!

[h3lblad3]

Hail Armok for this gift of fine Swallow Man, let him be praised.

I suggest that you first fill his chamber with water, then lava, his body will be encased in obsidian. Take said obsidian and turn it into a sword: it is guaranteed to be the most epic one of all time.

No.
A SPEAR!

[macdonellba]

EDIT: Erm, I actually meant to send this as a private message, but apparently I can't delete my accidental postings from the forum.