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[Ozarck]

using VonNost and variations as key in an asfgx cipher, I still get a pretty flat distribution of letters compared to english (too few of the common letters, too many of the uncommon).

[Parisbre56]

What if it's a simple  substitution cypher, where each letter changes to a new alphabet and if put one next to another, the first letter of each alphabet forms VonNost?

[Tomasque]

I know this may seem slightly irrelevant (or obvious) but since it's called the Doctor's Cipher, maybe the way to find the answer includes something that requires medical knowledge.

[Ozarck]

What if it's a simple  substitution cypher, where each letter changes to a new alphabet and if put one next to another, the first letter of each alphabet forms VonNost?

a simple substitution cipher from a five symbol text?

[NJW2000]

You sure he'd encrypt it using his own name?

I'd follow up my trigram = punctuation, bigram = letter idea, but am just too tired, tbh. But the trigram that comes up like 23 times, marked as 14 on the first page, has a delta in between two iterations, three times, so this may be important. Like, very, I'll probably have another crack tomorrow.

[Parisbre56]

What if it's a simple  substitution cypher, where each letter changes to a new alphabet and if put one next to another, the first letter of each alphabet forms VonNost?

a simple substitution cipher from a five symbol text?

Why 5? Depending on if you're taking two or three letter combinations it's more than that. I know it's unlikely, but if we're just saying whatever comes to mind, I just thought I'd just say what I thought and maybe hopefully if I'm lucky and the stars align inspire someone to come up with a solution.

I meant something like assign each letter combination a number and then pass the n-th combination of letters through the n-the alphabet and replace the letter with the number with the appropriate letter.


  1 2 3 4 5 6 7
1 V O N N O S T
2 W P O O P T U
3 X Q P P Q U V
etc.

[Ozarck]

I said five because that is the number of symbols in the Cipher. If we knew how they grouped (in twos, threes, singly, combined, in fives) then we could assign each group a value and work from there.

You describe something like a vignere Cipher. Edit: brainlock. can't think right now.

[piecewise]

Well, what amount of token hint do you guys want? Or am I the only person still working on this any significant amount?

I'm thinking 5 or 10 token's worth.

So is the lack of response about this a no to the hint?

[NJW2000]

Hold on the hint for a bit, guys? I might have a lead, though I doubt it. I also can't get near the clever person I asked for another 24 hours or so.

[TheBiggerFish]

Hold on the hint for a bit, guys? I might have a lead, though I doubt it. I also can't get near the clever person I asked for another 24 hours or so.

+1.
I'm gonna throw this at people, see if they can get anything.

[Hapah]

Well then, how about this. If no one has a good lead they're willing to share or anything similar by this time next week (Sunday the 11th), then we'll get a hint. How's that sound?

[Gentlefish]

A five token hint.

[Egan_BW]

49 token hint.

[TheBiggerFish]

49 token hint.

No.

[Hapah]

5 token hint next Sunday is just fine by me.