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Author Topic: The Doctor's Cipher.  (Read 36418 times)

NJW2000

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Re: The Doctor's Cipher.
« Reply #135 on: August 25, 2015, 06:06:29 am »

The 5x5 thing could be relevant if it really was in greek, as at least one of ancient and modern greek has 24 letters, and with 1 for space, it COULD just be digrams corresponding to words which must be translated. This doesn't seem particularly likely, but still.

If anyone needs help translating greek, I can give a bit.

It's not as simple as that, several people tried very quickly. That would just be a substitution cipher with pairs rather than single letters. I'm wondering if it could be in greek, as their alphabet is better for that.
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Urist McCoder

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Re: The Doctor's Cipher.
« Reply #136 on: August 25, 2015, 06:17:40 am »

Part of the issue is that everyone wants the prize. We need a team of people who don't care about the prize or as previously stated share the prize
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Parisbre56

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Re: The Doctor's Cipher.
« Reply #137 on: August 25, 2015, 08:43:28 am »

I don't know if I've miscounted, but I'm pretty sure there's an odd number of symbols. That means that it probably can't be just pairs, unless the final symbol is to be taken similar to its use in religious texts. As in "I am the Alpha and the Omega" meaning "the last" or "the end" for "end of cipher" or for "end of the universe".

NJW2000

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Re: The Doctor's Cipher.
« Reply #138 on: August 25, 2015, 09:15:27 am »

Unless the bottom was some kinda key, yeah.
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Urist McCoder

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Re: The Doctor's Cipher.
« Reply #139 on: August 25, 2015, 11:03:04 am »

No they can be pairs look at the link I posted earlier
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Parisbre56

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Re: The Doctor's Cipher.
« Reply #140 on: August 25, 2015, 11:21:44 am »

No they can be pairs look at the link I posted earlier
Can you pair an odd number of things? Because there's an odd number of symbols there.
Unless I've miscounted or you're suggesting part of the message is the key.

Urist McCoder

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Re: The Doctor's Cipher.
« Reply #141 on: August 25, 2015, 11:50:29 am »

In not sure what you mean
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Parisbre56

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Re: The Doctor's Cipher.
« Reply #142 on: August 25, 2015, 11:54:57 am »

ABA

Can the above be an encoded message that uses pairs?

Urist McCoder

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Re: The Doctor's Cipher.
« Reply #143 on: August 25, 2015, 01:46:19 pm »

Okay I miss understood
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piecewise

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Re: The Doctor's Cipher.
« Reply #144 on: August 27, 2015, 12:36:09 pm »

How close are we to needing a hint?

Ozarck

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Re: The Doctor's Cipher.
« Reply #145 on: August 27, 2015, 12:38:00 pm »

How close are we to needing a hint?
about eleven months.

Edit: I haven't had a lot of time or brainpower lately, but I am working on it again.

HavingPhun

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Re: The Doctor's Cipher.
« Reply #146 on: August 29, 2015, 06:54:51 pm »

How close are we to needing a hint?
about eleven months.

Edit: I haven't had a lot of time or brainpower lately, but I am working on it again.

I agree with this, I think we should still wait some time. This isn't going to be an easy thing. I suppose this might also matter to some people. How much would the prize be reduced token wise, if you gave this hint?
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piecewise

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Re: The Doctor's Cipher.
« Reply #147 on: August 29, 2015, 07:32:17 pm »

How close are we to needing a hint?
about eleven months.

Edit: I haven't had a lot of time or brainpower lately, but I am working on it again.

I agree with this, I think we should still wait some time. This isn't going to be an easy thing. I suppose this might also matter to some people. How much would the prize be reduced token wise, if you gave this hint?
Depends on the level of the hint. Something very vague might reduce it by like 3-5 tokens. Something blatant would be like half.

Egan_BW

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Re: The Doctor's Cipher.
« Reply #148 on: August 29, 2015, 09:32:23 pm »

I have no involvement in this so I say spoil the whole thing
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Empiricist

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Re: The Doctor's Cipher.
« Reply #149 on: August 29, 2015, 09:34:23 pm »

I say if we do have a hint, it should be the smallest possible. Then we continuously receive the same hint while being repeatedly charged the same cost, thus resulting in a situation where the prize eventually becomes negative and the person who cracks it gets fined for taking too long :P
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