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[alemagno12]

Oh.

[FallenAngel]

My trump card is x/(x^3), as x approaches 0.
Since when x equals .1, the equation is equal to 100, and when it equals .01, the equation is equal to 10000, as x approaches 0, the equation approaches, but never reaches, a technically infinite number. It remains finite, as logically, 0/(0^3) in this equation would be ∞, but as 0/0 is undefined, the equation never becomes infinite.
Please hold for the approximate value of the infinitesimal number.

[MagmaMcFry]

Is there an integer larger than your number? No. Therefore your number is not finite.

[FallenAngel]

I haven't exactly defined at which point x stops approaching 0.
However, I am hungry, so wait some time.

The infinitesimal number is 10 taken to -(hyper-G taken to hyper-G taken to Hyper-G...)
The stack of hyper-Gs continues on for G taken to hyper-G hyper-G times.

[MagmaMcFry]

In that case your number would be exactly 100↑²A(G)↑³G↑²A(G)↑³A(G), which is really quite laughably small compared to what we had in this thread so far.

[FallenAngel]

Well, that failed.
Anyone up for Calvinchess?

[MagmaMcFry]

Like this?

[FallenAngel]

Exactly what I had in mind.

[alemagno12]

My entry is largest possible number.
*the end*

[Putnam]

largest possible number is either:

1. not finite
2. a contradiction in terms

[alemagno12]

largest possible finite number that follows the rules

[MagmaMcFry]

largest possible finite number that follows the rules

All finite numbers follow the rules, but they don't have a maximum, so your number doesn't exist.

[Putnam]

largest possible finite number that follows the rules

Assume such a thing were to exist. Add one to your number; that number follows the rules. That's a contradiction.

[alemagno12]

Define n? to be the nth number that can't be comprensible.
100?.

[MagmaMcFry]

Define comprensible.