You can throw in a bit of maths to calculate the position of the edge of the circle in-situ (with a little bit of patience and understanding of how you describe a graph). Apologies for anyone allergic to algebra.
The following equation describes a circle in the x-y plane of radius 'r' around the origin:
x^2 + y^2 = r^2
If you want a circle that's (say) 25 squares in diameter (so r = 25/2 = 12.5 rounded
down to 12; this gives you 1 square in the middle of the diameter and 12 squares in a line either side, giving 25 in total), start by defining the square at the centre of your circle; this is the point 'x=0, y=0' or '(0,0)'
Rearranging the equation:
y = SQRT(r^2 - x^2)
Follow me through this:
At the point x=0, y = SQRT((12)^2 - 0) = 12
So the edge of the circle is 12 squares up and 12 squares down from (0,0)
At the point x=1 or x=(-1), y = SQRT((12)^2 - (1)^2) = +/-11.9582... -> round up to 12
So the edge of the circle is also 12 squares up and 12 squares down from both (-1,0) and (1,0)
At x=+/-2, y = SQRT((12)^2 - (2)^2) = +/-11.8322... -> round up to 12.
So the edge of the circle is again 12 squares up and 12 squares down from both (-2,0) and (2,0)
At x=+/-3, y = SQRT((12)^2 - (3)^2) = +/-11.6190... -> round up to 12
So the edge of the circle is yet again 12 squares up and 12 squares down from both (-3,0) and (3,0)
At x=+/-4, y = SQRT((12)^2 - (4)^2) = +/-11.3137... -> round down to 11
So the edge of the circle is 11 squares up and 11 squares down from both (-4,0) and (4,0)
etc, up to x=+/-12 where y=0
Essentially you're calculating the length of one of the sides of a right-angled triangle from knowing the length of the hypotenuse and one of the other sides. You might find using paint or other similar programs faster if you're not so confident with the maths but it might be useful otherwise, especially if you have a scientific calculator to hand