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[utunnels]

I did some !!science!!.
I embarked 30 times and checked the starting sevens.

Number of possible couples:

0 = 2 times (6.667%)
1 = 21 times (70%)
2 = 4 times (13.333%)
3 = 3 times (10%)

So if my method was correct, there were 23% chance there are at least 2 valid couples among the starting seven. The chance was actually higher than I expected.